recall that integral secu tanu du = secu
Let u=2x and you have du=2dx, so
integral 9 secu tanu du = 9secu = 9sec2x
Use the indicated substitution to evaluate the integral
integral 18sec(2x) tan(2x)dx, u=2x
1 answer
integral 18sec(2x) tan(2x)dx, u=2x
1 answer