Asked by yaya
A certain centrifuge produces a centripetal acceleration of magnitude exactly 1090g at a point 12.3 cm from the axis of rotation. Find the number of revolutions per second.
Answers
Answered by
Elena
Centripetal acceleration
a=ω²•R =(2πn)²•R =4π²n²•R =>
n=sqrt{aR/4π²} =sqrt{1090•9.8•0.123/4•π²}=5.77 rev/s
a=ω²•R =(2πn)²•R =4π²n²•R =>
n=sqrt{aR/4π²} =sqrt{1090•9.8•0.123/4•π²}=5.77 rev/s
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