P1V1 = P2V2
Post your work if you get stuck.
A sample of gas occupies 29 L under a pressure of 1.3 atm. What would the resulting volume be if the pressure were increased to 3.9 atm if the temprature did not change?
4 answers
(1.3 atm)(29L)=(P2)(3.9)
9.66=P2
9.66=P2
Correct; however, I would have rounded differently.
My answer waw 9.66666 and since 6 is over 5, I would add to the number to arrive at 9.7 L and not 9.66 L. You are allowed two significant digits (29, 1.3 and 3.9 all have two s.f. and in multiplication and division we are allowed the number with the least s.f. That means we may have two places). Thus I rounded to 9.7 Liters. Thanks for using Jiskha.
My answer waw 9.66666 and since 6 is over 5, I would add to the number to arrive at 9.7 L and not 9.66 L. You are allowed two significant digits (29, 1.3 and 3.9 all have two s.f. and in multiplication and division we are allowed the number with the least s.f. That means we may have two places). Thus I rounded to 9.7 Liters. Thanks for using Jiskha.
Thank you for your help.