A real estate salesperson bought promotional calendars and date books to give to her customers at the end of the year. The calendars cost $0.75 each, and the date books cost $0.40 each. She ordered a total of 600 promotional items and spent $380. How many of each item did she order?
3 answers
Ms. Sue, would you mind assisting me with this math problem?
Let c be the number of calender, and d be the number of datebooks.
The total number of items tells us that:
c + d = 600
Rearranging:
d = 600 - c
The total cost tells us that:
0.76 c + 0.40 d = 380
Substituting d = 600 - c:
0.75 c + 0.40 (600 - c) = 380
Simplify to solve for c:
...
c = ___
Use d = 600 - c to find d:
d = ___
Concluding:
c=___ calenders at $0.75ea and d=___ date books at $0.40ea, are 600 items that costs $380 in total.
The total number of items tells us that:
c + d = 600
Rearranging:
d = 600 - c
The total cost tells us that:
0.76 c + 0.40 d = 380
Substituting d = 600 - c:
0.75 c + 0.40 (600 - c) = 380
Simplify to solve for c:
...
c = ___
Use d = 600 - c to find d:
d = ___
Concluding:
c=___ calenders at $0.75ea and d=___ date books at $0.40ea, are 600 items that costs $380 in total.
Thank you Graham
1 answer