Question

I know that anything to the power of 0 is 1 but I need help with these 2 questions and check my answers:

(xy)^0 / (z^2a^1)=
(-2mn^2)^1 / (pqm)^0=
(xy^2z)^0= 1?

Negative Exponents: it says to leave answers with positive exponents only, I did all these questions so please check my answers:

y^2*y^-4 = my answer: y^-2 then changed to a positive = 1/y^2

1/m^-2 = m^2/1

x^2y^-1/x^5y^-2= my answer: x^-3y then changed to a positive = y/x^3

(7x^2y^-6)^-1= my answer: -7x^-2 y^6 then changed to a positve= y^6/7x^2

(c^2/3d^-1)^-2 = my answer: c^-4/3d^2 then changed to a positive = 3d^2/c^4

(2m^4n/3m^-1n^3)^-2= my answer:
2m^-8n^-2/3m^2n^-6, I don't know how to change this inot a positve, help

Answer 1

(xy)^0 / (z^2a^1)= 1/(z²a)
-2mn^2)^1 / (pqm)^0= 2mn^2
yes, one.

one the last one, you have to square the 3
others correct.

Answer 2

how do you sqaure the last one?? please show me how

Answer 3

is the last one the only one that is wrong, please show me how to do the last one

Answer 4

Look, the law of exponents applies to all... You had a 3^1 in the denominator, specifically

(3^1...)^-2 and that changes to 9 in the numerator. Law of exponents does not apply to just variables.

Answer 5

so the correct answer would be :
2m^-8n^-2/9m^2n^-6??

Answer 6

I like this last one:
(c^2/3d^-1)^-2 =
c^-4 / (3^-2 d^2)=

9/c^4d^2

check it please.

Answer 7

wait...so you were talking about this question: (c^2/3d^-1)^-2

I thought you were talking about this question:
(2m^4n/3m^-1n^3)^-2

so is my answer to this question (2m^4n/3m^-1n^3)^-2 correct?

Answer 8

how would you turn this question:(2m^4n/3m^-1n^3)^-2 into a positive?

Answer 9

Yess