Asked by bless
intergal xcosax^2dx =
Answers
Answered by
Graham
∫ x cos(ax^2) dx
= ∫(1/2a)cos(u) du, where u=ax^2, du=2ax dx
= (1/2a)sin(u) + C
= sin(ax^2)/(2a) + C
= ∫(1/2a)cos(u) du, where u=ax^2, du=2ax dx
= (1/2a)sin(u) + C
= sin(ax^2)/(2a) + C
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