Asked by Anon
Find the derivative of
y=sin(x)*(sinx+cosx)
y=sin(x)*(sinx+cosx)
Answers
Answered by
Steve
just use the product rule
If y = uv then
y' = u'v + uv'
where u=sinx and v=sinx+cosx
y' = cosx(sinx+cosx) + sinx(cosx-sinx)
= sin2x + cos2x
If y = uv then
y' = u'v + uv'
where u=sinx and v=sinx+cosx
y' = cosx(sinx+cosx) + sinx(cosx-sinx)
= sin2x + cos2x
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