Question
The density of iron is 7.87 g/cm3, and the average mass for one iron atom is 9.28×10-23 g.
How many atoms are there in a rectangular iron ingot measuring 3.00 cm × 3.00 cm × 9.00 cm?
How many atoms are there in a rectangular iron ingot measuring 3.00 cm × 3.00 cm × 9.00 cm?
Answers
you want to convert volume to #atoms. SO, start plugging in your conversion factors:
3.00cm*3.00cm*9.00cm = 81cm^3 * 7.87g/cm^3 / 9.28*10^-23g/atom = 6.87*10^24 atoms
3.00cm*3.00cm*9.00cm = 81cm^3 * 7.87g/cm^3 / 9.28*10^-23g/atom = 6.87*10^24 atoms
Related Questions
FE (iron) Using the information from the Periodic Table of Elements, identify the correct numbers...
When iron rusts and forms iron oxide, the iron oxide has more mass than the iron. Which statement co...
When iron rusts and forms iron oxide, the iron oxide has more mass than the iron. Which statement co...
Question 1
A)When iron rusts and forms iron oxide, the iron oxide has more mass than the iron. Whic...