Asked by Andy
The length of one side of an isosceles triangle is two times the base b.
This length is equal to (8b - 12),in.
What is the value of b?
This length is equal to (8b - 12),in.
What is the value of b?
Answers
Answered by
Reiny
8b - 12 = 2b
6b=12
b=2
base is 2, length = 16-12 = 4
6b=12
b=2
base is 2, length = 16-12 = 4
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