Asked by Lucas
Please Simplify:
(1/8)(40v−24y)−(1/7)(21v−35y+9)−(1/6)
(1/11)(55x−22)−(1/2)(18x−2v)
(1/8)(40v−24y)−(1/7)(21v−35y+9)−(1/6)
(1/11)(55x−22)−(1/2)(18x−2v)
Answers
Answered by
Steve
start with the parens:
(1/8)(40v−24y) = 5v-3y
(1/7)(21v−35y+9)−(1/6) = 3v-5y + 9/7 - 1/6
Now subtract to get
2v+2y - 47/42
do the other the same way
(1/8)(40v−24y) = 5v-3y
(1/7)(21v−35y+9)−(1/6) = 3v-5y + 9/7 - 1/6
Now subtract to get
2v+2y - 47/42
do the other the same way
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