Asked by Tania
Find the perimeter of KRN if K(2,9), R(-5,3), and N(0,-7). round to the nearest tenth.
Answers
Answered by
Henry
(KR)^2 = (-5-2)^2 + (3-9)^2 = 85
KR = 9.22
(RN)^2 = (-5-0)^2 + (3+7)^2 = 125
RN = 11.18
(KN)^2 = (0-2)^2 + (-7-9)^2 = 260
KN = 16.12
P = 9.22 + 11.18 + 16.12 = 36.5
KR = 9.22
(RN)^2 = (-5-0)^2 + (3+7)^2 = 125
RN = 11.18
(KN)^2 = (0-2)^2 + (-7-9)^2 = 260
KN = 16.12
P = 9.22 + 11.18 + 16.12 = 36.5
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