Asked by Serena

Hi. I need help on a couple of algebra problems. Can you please explain step by step how to do these?
Thanks.

ã(3x (whole thing has radical sign)
----
2y^3


^3(ã2x^4y^4)
------------ (the whole thing is cubed
9x

Answers

Answered by Serena
The squiggly A was originally a radical sign, but I guess it got changed.
Answered by Reiny
I will assume I am looking at

√(3x)/(2y^3) and

( √(2x^4 y^4) )/(9x)

are they multiplied or what ?

explain please
Answered by Serena
No. These two are both separate problems. The book asks to simplify each problem. And for the 2nd problem the index is a four.
Answered by Reiny
Still not too clear if the √ governs the whole thing in the first
Actually there is very little that can be done in terms of simplification.
If it is
√( 3x/(2y^3) ) remember that √ is equivalent to having an exponent of 1/2

so all you get is
√(3/2)x^(1/2) / y^(3/2) which is certainly not any more simpified

for the second I will read it as:

( √2x^4 y^4/(9x) )^3
= 2√2x^12 y^12/(729x^3

= (2√2/729)x^9 y^12

I think it was more "simplified" at the start.
Answered by Serena
Well for the first one, the answer s supposed to be 1ã6xy/2y^2.
The second problem's answer is xy/3 times the cubed root of 6y
Answered by Reiny
Can you see how important brackets are when typing on this forum?
I can't see any way to obtain those answers the way the questions were typed.

Answered by Serena
That's alright then. Thank you very much.
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