Asked by Serena
Hi. I need help on a couple of algebra problems. Can you please explain step by step how to do these?
Thanks.
ã(3x (whole thing has radical sign)
----
2y^3
^3(ã2x^4y^4)
------------ (the whole thing is cubed
9x
Thanks.
ã(3x (whole thing has radical sign)
----
2y^3
^3(ã2x^4y^4)
------------ (the whole thing is cubed
9x
Answers
Answered by
Serena
The squiggly A was originally a radical sign, but I guess it got changed.
Answered by
Reiny
I will assume I am looking at
√(3x)/(2y^3) and
( √(2x^4 y^4) )/(9x)
are they multiplied or what ?
explain please
√(3x)/(2y^3) and
( √(2x^4 y^4) )/(9x)
are they multiplied or what ?
explain please
Answered by
Serena
No. These two are both separate problems. The book asks to simplify each problem. And for the 2nd problem the index is a four.
Answered by
Reiny
Still not too clear if the √ governs the whole thing in the first
Actually there is very little that can be done in terms of simplification.
If it is
√( 3x/(2y^3) ) remember that √ is equivalent to having an exponent of 1/2
so all you get is
√(3/2)x^(1/2) / y^(3/2) which is certainly not any more simpified
for the second I will read it as:
( √2x^4 y^4/(9x) )^3
= 2√2x^12 y^12/(729x^3
= (2√2/729)x^9 y^12
I think it was more "simplified" at the start.
Actually there is very little that can be done in terms of simplification.
If it is
√( 3x/(2y^3) ) remember that √ is equivalent to having an exponent of 1/2
so all you get is
√(3/2)x^(1/2) / y^(3/2) which is certainly not any more simpified
for the second I will read it as:
( √2x^4 y^4/(9x) )^3
= 2√2x^12 y^12/(729x^3
= (2√2/729)x^9 y^12
I think it was more "simplified" at the start.
Answered by
Serena
Well for the first one, the answer s supposed to be 1ã6xy/2y^2.
The second problem's answer is xy/3 times the cubed root of 6y
The second problem's answer is xy/3 times the cubed root of 6y
Answered by
Reiny
Can you see how important brackets are when typing on this forum?
I can't see any way to obtain those answers the way the questions were typed.
I can't see any way to obtain those answers the way the questions were typed.
Answered by
Serena
That's alright then. Thank you very much.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.