Asked by Christina
A 22.8 kg turntable with a radius of 47 cm
is covered with a uniform layer of dry ice
that has a mass of 4.08 kg. The angular
speed of the turntable and dry ice is initially
0.52 rad/s, but it increases as the dry ice
evaporates.
What is the angular speed of the turntable
once all the dry ice has evaporated? Answer
in units of rad/s. 1.0 m
is covered with a uniform layer of dry ice
that has a mass of 4.08 kg. The angular
speed of the turntable and dry ice is initially
0.52 rad/s, but it increases as the dry ice
evaporates.
What is the angular speed of the turntable
once all the dry ice has evaporated? Answer
in units of rad/s. 1.0 m
Answers
Answered by
drwls
You are probably suppoased to assume that the turntable is frictionless and "coasting" (unpowered) while the dry ice evaporates. This is a rather unrealistic assumption
Anyway, in that case, you should assume that angular momentum is conserved.
I1 w1 = I2 w2.
If the dry ice is evenly distributed, the moment of inertia I is proportional to total mass, M. Therefore
M1 w1 = M2 w2.
w2 = (22.8)/(22.8-4.7) x 0.52
Anyway, in that case, you should assume that angular momentum is conserved.
I1 w1 = I2 w2.
If the dry ice is evenly distributed, the moment of inertia I is proportional to total mass, M. Therefore
M1 w1 = M2 w2.
w2 = (22.8)/(22.8-4.7) x 0.52
Answered by
drwls
You are probably supposed to assume that the turntable is frictionless and "coasting" (unpowered) while the dry ice evaporates. This is a rather unrealistic assumption
Anyway, in that case, you should assume that angular momentum is conserved.
I1 w1 = I2 w2.
If the dry ice is evenly distributed, the moment of inertia I is proportional to total mass, M. Therefore
M1 w1 = M2 w2.
w2 = [(22.8 + 4.7)/(22.8)] x 0.52
Anyway, in that case, you should assume that angular momentum is conserved.
I1 w1 = I2 w2.
If the dry ice is evenly distributed, the moment of inertia I is proportional to total mass, M. Therefore
M1 w1 = M2 w2.
w2 = [(22.8 + 4.7)/(22.8)] x 0.52
Answered by
bobpursley
If you model the turntable-ice mixture, then the moment of inertia will be proportional to mass.
wf=Iinitial/I final* wi
=k(4.08+22.8)/k(22.8) * .52 rad/sec
wf=Iinitial/I final* wi
=k(4.08+22.8)/k(22.8) * .52 rad/sec
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.