Asked by Unknown
How did he get 15 moles?
What is the molarity of a 5.00 x 102 ml solution containing 2490 g of KI?
5.00*10^2ml = 500ml = .5L
KI has molar mass 166, so you have 15 moles of KI
15moles/.5L = 30moles/L = 30M
What is the molarity of a 5.00 x 102 ml solution containing 2490 g of KI?
5.00*10^2ml = 500ml = .5L
KI has molar mass 166, so you have 15 moles of KI
15moles/.5L = 30moles/L = 30M
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