Asked by Adalaide

Frances wanted to prepare a 0.0285M standard solution of LiCl. She weighed out 27.5g of solid LiCl. She had plenty of water available. What volume of the solution was she able to prepare?
Answered by Steve
how many moles in 27.5g?
We only need .0285 moles/liter
so divide the # moles of salt by the molarity to get the volume.
Answered by Adalaide
Thank you so much for your help. Once I got the formula to convert grams to moles, this was a lot of help. But could you check my work for me? I converted the grams to moles and got 0.648737909 mol LiCl. Then I divided that by 0.0285M and got 22.76273365 L which I rounded to be 22.8 liters of LiCl.
Answered by Anonymous
So is 22.8 the correct answer?
Answered by Adalaide
I'm almost 100% sure it is.
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