Asked by Anonnnn
g(x)=(x^2-4)/(4x); g(n-3)
how do you solve thiss?
how do you solve thiss?
Answers
Answered by
bobpursley
g(x)=(x-4)(x+4)/4x
g(n-3)=(n-7)(n+1)/(4n-12)
g(n-3)=(n-7)(n+1)/(4n-12)
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