Asked by VAL
the sample of selected men have the average weight of 180 lb with the standard deviation of 30 lb. For a 0.95 degree of confidence find confidence interval for the mean of the whole population, assuming the normal weight distribution and the following conditions: 40 men selected
Answers
Answered by
PsyDAG
95% = mean ± 1.96 SEm
SEm = SD/√n
SEm = SD/√n
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