Asked by Shawn
A silicon ingot, which should contain 10^16 boron atoms/cm3, is to be grown by the Czochralski technique. What
concentration of boron atoms should be in the melt to give the required concentration in the ingot ? If the initial load of Si in the crucible is 60 kg, how many grams of boron (atomic weight 10.8) should be added ? The density of molten silicon is 2.53 gm/cm3 and segregation co-eff ko for boron is 0.8.
concentration of boron atoms should be in the melt to give the required concentration in the ingot ? If the initial load of Si in the crucible is 60 kg, how many grams of boron (atomic weight 10.8) should be added ? The density of molten silicon is 2.53 gm/cm3 and segregation co-eff ko for boron is 0.8.
Answers
Answered by
Bot
To determine the concentration of boron atoms in the melt, we can use the segregation coefficient (ko) formula:
Concentration in ingot = ko × Concentration in melt
10^16 atoms/cm3 = 0.8 × Concentration in melt
Concentration in melt = (10^16 atoms/cm3) / 0.8
Concentration in melt = 1.25 × 10^16 atoms/cm3
Now we need to find the number of moles of silicon and boron. First, let's find the volume of molten silicon:
60 kg = 60000 g
Volume = mass / density
Volume = 60000 g / 2.53 g/cm3
Volume = 23715.42 cm3
Now, let's find the number of silicon atoms and their molar quantity:
Silicon atoms volume = Volume × density
Silicon atoms = 23715.42 cm3 × 5.0 × 10^22 atoms/cm3(Avogadro constant)
Silicon atoms = 1.1857 × 10^28 atoms
Number of Moles (silicon) = Number of atoms / (Avogadro constant)
Number of Moles (silicon) = 1.1857 × 10^28 atoms / (6.022 × 10^23 atoms/mol)
Number of Moles (silicon) = 196,938.19 moles
Now we find the amount of boron atoms in the molten silicon:
Boron atoms = Volume × Concentration in melt
Boron atoms = 23715.42 cm3 × 1.25 × 10^16 atoms/cm3
Boron atoms = 2.9644 × 10^21 atoms
Now, let's find the molar quantity of boron:
Number of Moles (boron) = Number of atoms / (Avogadro constant)
Number of Moles (boron) = 2.9644 × 10^21 atoms / (6.022 × 10^23 atoms/mol)
Number of Moles (boron) = 4,920.96 moles
Now we have the molar quantities of silicon and boron, and we can find the amount of boron in grams that should be added:
Grams (boron) = Number of moles × atomic weight
Grams (boron) = 4,920.96 moles × 10.8 g/mol
Grams (boron) = 53,146.36 g
Therefore, to achieve the desired concentration of boron atoms in the silicon ingot, 53,146.36 grams of boron should be added to the initial load of 60 kg silicon in the crucible.
Concentration in ingot = ko × Concentration in melt
10^16 atoms/cm3 = 0.8 × Concentration in melt
Concentration in melt = (10^16 atoms/cm3) / 0.8
Concentration in melt = 1.25 × 10^16 atoms/cm3
Now we need to find the number of moles of silicon and boron. First, let's find the volume of molten silicon:
60 kg = 60000 g
Volume = mass / density
Volume = 60000 g / 2.53 g/cm3
Volume = 23715.42 cm3
Now, let's find the number of silicon atoms and their molar quantity:
Silicon atoms volume = Volume × density
Silicon atoms = 23715.42 cm3 × 5.0 × 10^22 atoms/cm3(Avogadro constant)
Silicon atoms = 1.1857 × 10^28 atoms
Number of Moles (silicon) = Number of atoms / (Avogadro constant)
Number of Moles (silicon) = 1.1857 × 10^28 atoms / (6.022 × 10^23 atoms/mol)
Number of Moles (silicon) = 196,938.19 moles
Now we find the amount of boron atoms in the molten silicon:
Boron atoms = Volume × Concentration in melt
Boron atoms = 23715.42 cm3 × 1.25 × 10^16 atoms/cm3
Boron atoms = 2.9644 × 10^21 atoms
Now, let's find the molar quantity of boron:
Number of Moles (boron) = Number of atoms / (Avogadro constant)
Number of Moles (boron) = 2.9644 × 10^21 atoms / (6.022 × 10^23 atoms/mol)
Number of Moles (boron) = 4,920.96 moles
Now we have the molar quantities of silicon and boron, and we can find the amount of boron in grams that should be added:
Grams (boron) = Number of moles × atomic weight
Grams (boron) = 4,920.96 moles × 10.8 g/mol
Grams (boron) = 53,146.36 g
Therefore, to achieve the desired concentration of boron atoms in the silicon ingot, 53,146.36 grams of boron should be added to the initial load of 60 kg silicon in the crucible.
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