Asked by Aaron
If m <DCE=4x+15 and m<ECF=6X-5 ,find m<DCE
Answers
Answered by
Henry
The angles are assumed to be complimentary(sum=90o).
DCE + ECF = 90o
4x+15 + 6x-5 = 90
10x + 10 = 90
10x = 80
X = 8
DCE = 4*8 + 15 = 47o
DCE + ECF = 90o
4x+15 + 6x-5 = 90
10x + 10 = 90
10x = 80
X = 8
DCE = 4*8 + 15 = 47o
Answered by
catalina
Álgebra if a supplement of an angle has a measure 78 less than the measure of the angle,what are the measures of the ángeles?
Answered by
Anonymous
find the measure of angle DCE.
Answered by
kenneth
can you show the angle to get the answer
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