Asked by how
6b-3 / 3b^2-12
Answers
Answered by
Steve
3(b-2) / 3(b^2-4)
= 3(b-2) / 3(b-2)(b+2)
= 1/(b+2)
= 3(b-2) / 3(b-2)(b+2)
= 1/(b+2)
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