Asked by Shane
Find the ratio of the coefficients of the 4th and 6th terms in the expansion of (1 + 2x)^16
Answers
Answered by
Reiny
You had a similar question like this before
http://www.jiskha.com/display.cgi?id=1375847416
anyway...
(1+2x)^16
= 1 + C(16,1) (2x)^1 + C(16,2) (2x)^2 + ...
term 4 = C(16,3) (2x)^3 = 4480x^3
term 6 = C(16,5) (2x)^5 = 139776x^5
4480 : 139776 = 5:156
http://www.jiskha.com/display.cgi?id=1375847416
anyway...
(1+2x)^16
= 1 + C(16,1) (2x)^1 + C(16,2) (2x)^2 + ...
term 4 = C(16,3) (2x)^3 = 4480x^3
term 6 = C(16,5) (2x)^5 = 139776x^5
4480 : 139776 = 5:156
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