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Let f(x) = \sqrt[3] x. The equation of the tangent line to f(x) at x = 8 is y = (1/12)(x-8)+2. Using this, we find our approximation for sqrt[3] {8.1} is ?
12 years ago

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Answered by Steve
ummm, try (1/12)(8.1-8)+2
12 years ago
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Let f(x) = \sqrt[3] x. The equation of the tangent line to f(x) at x = 8 is y = (1/12)(x-8)+2. Using this, we find our approximation for sqrt[3] {8.1} is ?

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