Asked by nick
a feather is dropped on the moon from a height of 1.4 meters.the acceleration of the moon is 1.67 m/s determine the time for the feather to fall on the surface of
the moon
the moon
Answers
Answered by
Henry
Assuming no wind:
Vo*t + 0.5g*t^2 = 1.4 m.
0 + 0.5*1.63*t^2 = 1.4
0.815t^2 = 1.4
t^2 = 1.72
t = 1.31 s.
Vo*t + 0.5g*t^2 = 1.4 m.
0 + 0.5*1.63*t^2 = 1.4
0.815t^2 = 1.4
t^2 = 1.72
t = 1.31 s.
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