## To find the number of three-digit or four-digit even numbers that can be formed from the numbers 2, 3, 5, and 7, we need to consider a few conditions:

1. The last digit must be even, which means it can only be 2 or 6.

2. The first digit cannot be zero.

Now let's break down the problem into two cases:

Case 1: Four-digit numbers:

If we consider four-digit numbers, then the first digit can be any of the numbers 2, 3, 5, or 7. After choosing the first digit, the second and third digits can be any of the four numbers. Finally, the last digit must be even, which means it can only be 2 or 6. Therefore, we have:

4 choices for the first digit Γ 4 choices for the second digit Γ 4 choices for the third digit Γ 2 choices for the last digit = 4 Γ 4 Γ 4 Γ 2 = 128

Case 2: Three-digit numbers:

If we consider three-digit numbers, then the first digit can be any of the numbers 2, 3, 5, or 7. After choosing the first digit, the second digit can be any of the four numbers, and the last digit must be even, which means it can only be 2 or 6. Therefore, we have:

4 choices for the first digit Γ 4 choices for the second digit Γ 2 choices for the last digit = 4 Γ 4 Γ 2 = 32

Now, to get the final answer, we add the number of four-digit numbers and three-digit numbers together:

128 + 32 = 160

Therefore, the correct answer is not listed among the given options.