Asked by ja cle
if you have 4350 gallons of 80 degree water and add 60 gallons of 125 degree water how warm would the water temp get.
Answers
Answered by
Steve
assuming you mix them, treat it as a general mixture problem, where the total "energy" must add up:
4350*80 + 60*125 = (4350+60)x
x = 80.6
Not much of a change, but then 60 gallons is pretty small compared to 4350 gallons.
4350*80 + 60*125 = (4350+60)x
x = 80.6
Not much of a change, but then 60 gallons is pretty small compared to 4350 gallons.
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