Asked by Erin
A woman with mass 50.0kg is standing on the rim of a large disk that is rotating at 0.500rev/s about an axis perpendicular to it through its center. The disk has a mass of 110kg and a radius of 4.00m. Calculate the magnitude of the total angular momentum of the woman-plus-disk system, assuming that you can treat the woman as a point.
Answers
Answered by
Damon
M = 110
m = 50
r = 4
The moment of inertia of the disk about the axis is .5 M r^2
The moment of inertia of the woman about the axis is m r^2
Total moment of inertia I = .5 Mr^2 + m r^2
angular velocity w = 2 pi * .5 radians/second
angular momentum = I w = [.5 M + m] r^2* (2 pi *.5)
m = 50
r = 4
The moment of inertia of the disk about the axis is .5 M r^2
The moment of inertia of the woman about the axis is m r^2
Total moment of inertia I = .5 Mr^2 + m r^2
angular velocity w = 2 pi * .5 radians/second
angular momentum = I w = [.5 M + m] r^2* (2 pi *.5)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.