M = 110
m = 50
r = 4
The moment of inertia of the disk about the axis is .5 M r^2
The moment of inertia of the woman about the axis is m r^2
Total moment of inertia I = .5 Mr^2 + m r^2
angular velocity w = 2 pi * .5 radians/second
angular momentum = I w = [.5 M + m] r^2* (2 pi *.5)
A woman with mass 50.0kg is standing on the rim of a large disk that is rotating at 0.500rev/s about an axis perpendicular to it through its center. The disk has a mass of 110kg and a radius of 4.00m. Calculate the magnitude of the total angular momentum of the woman-plus-disk system, assuming that you can treat the woman as a point.
1 answer
2 answers