Asked by catherine
A 1.0-m thin rod of aluminum is laid end-to-end with a 1.0-m thin rod of steel. The rods
are initially at 25 oC. What is the total length of both rods when heated to 450 oC?
are initially at 25 oC. What is the total length of both rods when heated to 450 oC?
Answers
Answered by
Elena
L=L₁+L₂=L₀₁+ΔL₁ +L₀₂ + ΔL ₂=
= L₀₁+α₁•L₀₁•ΔT +L₀₂ + α₂•L₀₂•ΔT=
=1+ 23.1•10⁻⁶(450-25) +1+ 12•10⁻⁶(450-25) =
=2.015 m
= L₀₁+α₁•L₀₁•ΔT +L₀₂ + α₂•L₀₂•ΔT=
=1+ 23.1•10⁻⁶(450-25) +1+ 12•10⁻⁶(450-25) =
=2.015 m
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