Asked by victoria
How many atoms of each type are represented in each of the following? f. 5Fe(No3)2 g. 4Mg3(PO4)2 h. 2(NH4)2SO4
Answers
Answered by
DrBob222
You need to know the following rules.
1. Subscripts (the 3 in NO3 in f) multiply the preceding atom while the 2 in (NO3)2 multiply everything inside the parentheses. So you have 2 N atoms and 6 O atoms in f (so far--since this doesn't count the 5 coefficient).
2. Coefficients such as the 5 in f multiply everything that follows.
Therefore, you have 5 Fe atoms, 2*5 = 10 N atoms and 2*3*5 = 30 O atoms in f.
For 4Mg3(PO4)2 you have 12 Mg, 8 P and 32 O atoms.
1. Subscripts (the 3 in NO3 in f) multiply the preceding atom while the 2 in (NO3)2 multiply everything inside the parentheses. So you have 2 N atoms and 6 O atoms in f (so far--since this doesn't count the 5 coefficient).
2. Coefficients such as the 5 in f multiply everything that follows.
Therefore, you have 5 Fe atoms, 2*5 = 10 N atoms and 2*3*5 = 30 O atoms in f.
For 4Mg3(PO4)2 you have 12 Mg, 8 P and 32 O atoms.
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