Asked by Anonymous
An equilibrium mixture at 225∘C contains 8.0×10−2M NH3 and 0.20M H2 for the reaction
3H2(g)+N2(g)←→2NH3(g)
If the Kc at this temperature is 1.7×102, what is the equilibrium concentration of N2?
3H2(g)+N2(g)←→2NH3(g)
If the Kc at this temperature is 1.7×102, what is the equilibrium concentration of N2?
Answers
Answered by
Graham
Kc = [NH3]^2 / [N2] [H2]^3
so [N2] = [NH3]^2 / [H2]^3 Kc
so [N2] = [NH3]^2 / [H2]^3 Kc
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