Asked by a
What is the Kc for the following equilibrium at 500∘C,
N2(g)+3H2(g)⇌2NH3(g)
[H2] = 0.50M , [N2] = 0.50M , [NH3] = 2.0M ?
N2(g)+3H2(g)⇌2NH3(g)
[H2] = 0.50M , [N2] = 0.50M , [NH3] = 2.0M ?
Answers
Answered by
Graham
(Eh? Gas activity measured as molar concentration instead of partial pressure? Odd, but...)
Kc = {NH3]^2 / [H2]^3 [N2]
= (2.0M)^2 / (0.50M)^3 (0.50M)
= 64 M^(-2)
Kc = {NH3]^2 / [H2]^3 [N2]
= (2.0M)^2 / (0.50M)^3 (0.50M)
= 64 M^(-2)
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