Asked by Justin

When 1.60 multiplied by 105 J of heat enters a cherry pie initially at 20.0°C, its entropy increases by 470 J/K. What is its final temperature (C)?

Answers

Answered by drwls
delta S = entropy change = 1.6*10^5*[1/293 - 1/T2] = 470

Solve for T2
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