Asked by Justin
When 1.60 multiplied by 105 J of heat enters a cherry pie initially at 20.0°C, its entropy increases by 470 J/K. What is its final temperature (C)?
Answers
Answered by
drwls
delta S = entropy change = 1.6*10^5*[1/293 - 1/T2] = 470
Solve for T2
Solve for T2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.