Asked by Alice
A hand-driven tire pump has a 2.50 cm diameter piston and a maximum stroke of 31.0 cm.
(a) How much work do you do in one stroke if the average gauge pressure is 2.40 multiplied by 105 N/m2 (about 35 psi)? (You may consider this an isothermal process.)
(b) What average force do you exert on the piston, neglecting friction and gravity?
(a) How much work do you do in one stroke if the average gauge pressure is 2.40 multiplied by 105 N/m2 (about 35 psi)? (You may consider this an isothermal process.)
(b) What average force do you exert on the piston, neglecting friction and gravity?
Answers
Answered by
bobpursley
force on piston: pressure*area=force
work done: PV=work
work done: PV=work
Answered by
Alice
I don't know which are the "area" and "V". Can you show me the steps. Thanks.
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