Asked by Jon
1)An electromagnetic wave is produced by:
an accelerating charged particle or changing magnetic fields.
2)Find the period of an electromagnetic wave of wavelength 2.20 x 10^-2 m.
3.00 x 10^8 * 2.20 x 10^-2
= 6.60 x 10^6 s
an accelerating charged particle or changing magnetic fields.
2)Find the period of an electromagnetic wave of wavelength 2.20 x 10^-2 m.
3.00 x 10^8 * 2.20 x 10^-2
= 6.60 x 10^6 s
Answers
Answered by
bobpursley
2) 1/period*wavelength=speedoflight
period=wavelength/speedoflight.
Also, think about your answer. A million seconds for one period? Goodness.
period=wavelength/speedoflight.
Also, think about your answer. A million seconds for one period? Goodness.
Answered by
Jon
2)I don't really understand 1/period*wavelength. I can't multiply period times wavelength if I don't know the period. but I did get a different answer. my book doesnt show me how to find the period I just used wavelength-frequency relationship for a wave equation to find the frequency
2.20 x 10^-2/3.00 x 10^8
= 7.33 x 10^-11
these are my choices by the way:
A)1.36 x 10^10
B)4.54 x 10^1
C)7.33 x 10^-11
D)6.60 x 10^6
2.20 x 10^-2/3.00 x 10^8
= 7.33 x 10^-11
these are my choices by the way:
A)1.36 x 10^10
B)4.54 x 10^1
C)7.33 x 10^-11
D)6.60 x 10^6
Answered by
drwls
frequency = (speed of light)/(wavelength)
= 3*10^8 m/s/(2.2*10^-2 m)
Looks like (A) to me.
All I did was rearrange the equation BobPursley gave you.
If you would label your calculations with dimensions, and write down your equations, it would be easier for you to find your own errors. Once again, it seems you are just plugging in numbers at random.
= 3*10^8 m/s/(2.2*10^-2 m)
Looks like (A) to me.
All I did was rearrange the equation BobPursley gave you.
If you would label your calculations with dimensions, and write down your equations, it would be easier for you to find your own errors. Once again, it seems you are just plugging in numbers at random.
Answered by
Jon
thank you but no I did not 3.00 x 10^8 is the speed of light constant I got from my book not out of my head that's what I use to find the wavelength
Answered by
Jon
the answer was C
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