Tap a filled for 8 mins=8x6=48 lit.
Tap b drained for 6 mins=6x2=12 lit.
Water remaining=48-12=36 lit=36000ml
Ht of water in tank=36000/(50x40)=36/2=18 cm
Tap b drained for 6 mins=6x2=12 lit.
Water remaining=48-12=36 lit=36000ml
Ht of water in tank=36000/(50x40)=36/2=18 cm
Using the calculations of anonymous of 36 L of water after both taps are turned of,
h/28 = 36/56
h = 28(36/56) = 18
the water is 18 cm deep
First, let's calculate the initial volume of water in the tank:
Volume = Length x Width x Height
Volume = 50 cm x 40 cm x 28 cm
Volume = 56,000 cm³
Now, let's calculate the amount of water flowing in and out for each tap:
Tap A: Flow rate = 6 liters per minute
After 2 minutes, the amount of water filled by tap A = Flow rate x Time = 6 liters/min x 2 min = 12 liters
Tap B: Flow rate = 2 liters per minute
After 6 minutes, the amount of water drained by tap B = Flow rate x Time = 2 liters/min x 6 min = 12 liters
Since the amount of water filled by tap A and drained by tap B is the same, the net change in volume is zero.
Final volume = Initial volume + amount of water filled - amount of water drained
Final volume = 56,000 cm³ + 12 liters - 12 liters = 56,000 cm³
Now, let's calculate the depth of water left in the tank:
Depth = Final volume / (Length x Width)
Depth = 56,000 cm³ / (50 cm x 40 cm)
Depth = 56,000 cm³ / 2,000 cm²
Depth = 28 cm
Therefore, the depth of water left in the tank is 28 cm.