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Tap A was turned on to fill a rectangular tank of 50 cm by 40 cm by 28 cm with water at a rate of 6 liters per minute. After 2...Asked by isaac
tap a was turned on to fill a rectangular tank of 50cm by 40cm by 28cm with water at a rate of 6 liters per minute. after 2 minutes, tap b was turned on to drain water from the tank at a rate of 2 liters per minutes. 6 minutes after tap b was turned on, both taps were tuned off. find the depth of water left in the tank
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Answered by
Anonymous
Tap a filled for 8 mins=8x6=48 lit.
Tap b drained for 6 mins=6x2=12 lit.
Water remaining=48-12=36 lit=36000ml
Ht of water in tank=36000/(50x40)=36/2=18 cm
Tap b drained for 6 mins=6x2=12 lit.
Water remaining=48-12=36 lit=36000ml
Ht of water in tank=36000/(50x40)=36/2=18 cm
Answered by
Reiny
A full tank will hold 56 L
Using the calculations of anonymous of 36 L of water after both taps are turned of,
h/28 = 36/56
h = 28(36/56) = 18
the water is 18 cm deep
Using the calculations of anonymous of 36 L of water after both taps are turned of,
h/28 = 36/56
h = 28(36/56) = 18
the water is 18 cm deep
Answered by
Debela Duguma
Trig aplication meseramants width of lake
Answered by
Debela Duguma
Haw can solev this qen trig application measruments width of lake?
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