Asked by John Smith

You decide to make a simple pendulum by attaching a bowling ball to a very light wire and suspending it from the ceiling in your garage. The length of the wire is 1.75 m and the mass of the bowling ball is 5 kg. If you pull the bowling ball back an angle of 15 degrees from the vertical and release it, how fast will the bowling ball be moving when it passes through equilibrium?

Answers

Answered by Steve
PE of ball when released is mgh
KE of ball at bottom of swing is the same, and is 1/2 mv^2.

get PE, solve for v
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