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The density of ice is 917 kg/m3, and the density of sea water is 1025 kg/m3. A swimming polar bear climbs onto a piece of float...
The density of ice is 917 kg/m3, and the density of sea water is 1025 kg/m3. A swimming polar bear climbs onto a piece of floating ice that has a volume of 6.76 m3. What is the weight of the heaviest bear that the ice can support without sinking completely beneath the water?
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Answered by
Elena
http://www.phy.ilstu.edu/~holland/phy108/Homework%2015%20solution.pdf
http://answers.yahoo.com/question/index?qid=20120322205457AAh2i77
http://answers.yahoo.com/question/index?qid=20120322205457AAh2i77
Answered by
Henry
Di + Db = Dsw
917 + Db = 1025 kg/m^3
Db = 108 kg/m^3 = Density of the bear.
Mass of bear = 6.76m^3*108kg/m^3=730 kg
Wt. of bear = 730kg * 9.8N/kg = 7154 N.
917 + Db = 1025 kg/m^3
Db = 108 kg/m^3 = Density of the bear.
Mass of bear = 6.76m^3*108kg/m^3=730 kg
Wt. of bear = 730kg * 9.8N/kg = 7154 N.
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