Asked by Drake
                What is the maximum value of f(f(x)) in the domain 4≤x≤7 for the function
f(x)=x^2−10x+22?
            
        f(x)=x^2−10x+22?
Answers
                    Answered by
            Reiny
            
    let y = f(f(x))
= (x^2 - 10x + 22)^2 - 10(x^2 - 10x + 22) + 22
dy/dx = 2(x^2 - 10x + 22)(2x - 10) - 20x + 100
= 0 for a max
(x^2 - 10x + 22)(2x-10) - 10(2x - 10)=0
(2x-10)(x^2 - 10x + 22 - 10) = 0
x = 5 or x = appr 8.6 or appr 1.4 , both of which lie outside our given domain
f(f(5)) = 61
f(f(4)) = 46
f(f(7)) = 13
So the max in the given domain is 61
    
= (x^2 - 10x + 22)^2 - 10(x^2 - 10x + 22) + 22
dy/dx = 2(x^2 - 10x + 22)(2x - 10) - 20x + 100
= 0 for a max
(x^2 - 10x + 22)(2x-10) - 10(2x - 10)=0
(2x-10)(x^2 - 10x + 22 - 10) = 0
x = 5 or x = appr 8.6 or appr 1.4 , both of which lie outside our given domain
f(f(5)) = 61
f(f(4)) = 46
f(f(7)) = 13
So the max in the given domain is 61
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