Asked by ROBIN

solve for theda given 0<theda<2pi
cos theta= - (sqrt 3)/ 2
Answered by Steve
you know that cos π/6 = √3/2
You also know that cos(x) < 0 in QII,QIII
So, ...
Answered by ROBIN
so ould it be sin pi.6 and tan pi/6??
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