Question
Let ABCDEF be an equiangular hexagon with perimeter 98 such that EF=2CD=4AB and BC=2FA. What is the length of EF?
Answers
Steve
opposite sides must be equal, so if AB=x, we have
2(x)+2(2x)+2(4x) = 98
7x = 49
x = 7
EF = 4*7 = 28
2(x)+2(2x)+2(4x) = 98
7x = 49
x = 7
EF = 4*7 = 28