Asked by Xian
A 2.4kg ball falling vertically hits the floor with a speed of 2.5m/s and rebounds with a speed of 1.5m/s. What is the impulse exerted on the floor?
Answers
Answered by
Henry
Impulse = m*V1-m*V2
Impulse = 2.4*2.5 - 2.4*1.5 = 2.4kgm/s
Impulse = 2.4*2.5 - 2.4*1.5 = 2.4kgm/s
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.