Asked by Xian

A 2.4kg ball falling vertically hits the floor with a speed of 2.5m/s and rebounds with a speed of 1.5m/s. What is the impulse exerted on the floor?

Answers

Answered by Henry
Impulse = m*V1-m*V2
Impulse = 2.4*2.5 - 2.4*1.5 = 2.4kgm/s
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