Asked by Jack
Find all solutions of the equation. Check your solutions in the original equation. (Enter your answers from smallest to largest. Enter NONE in any unused answer blanks.)
16t^2/3 + 40t^1/3 + 25 = 0
16t^2/3 + 40t^1/3 + 25 = 0
Answers
Answered by
Steve
let u = t^1/3 so we have
16u^2 + 40u + 25 = 0
(4u+5)^2 = 0
so, 4u+5 = 0
u = -5/4
so the only solution is t = -∛(5/4)
16u^2 + 40u + 25 = 0
(4u+5)^2 = 0
so, 4u+5 = 0
u = -5/4
so the only solution is t = -∛(5/4)
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