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For each of the following scenarios, indicate whether the oscillation period of the block becomes shorter, longer or remains un...Question
For each of the following scenarios, indicate whether the oscillation period of the pendulum becomes shorter, longer or remains unchanged. Note: you must clearly mark your answer (for example, highlight it in red) from the multiple-choice list below and you must provide an explanation of your answer to receive credit. Review: course textbook (section 9.1).
a. The pendulum is transported to another planet where the acceleration due to gravity is smaller.
i. Shorter
ii. Longer
iii. Unchanged
Explanation:
b. The mass of the pendulum increases.
i. Shorter
ii. Longer
iii. Unchanged
Explanation:
c. The length of the pendulum decreases (i.e., the pendulum arm is shortened).
i. Shorter
ii. Longer
iii. Unchanged
Explanation:
d. The distance the pendulum travels or how far it travels from side to side (i.e., the amplitude of oscillation) is reduced.
i. Shorter
ii. Longer
iii. Unchanged
Explanation:
2. Consider a block attached to a spring shown in Figure 9.1.5 of the textbook.
For each of the following scenarios, indicate whether the oscillation period of the block becomes shorter, longer or remains unchanged. Note: you must clearly mark your answer (for example, highlight it in red) from the multiple-choice list below and you must provide an explanation of your answer to receive credit. Review: course textbook (section 9.1).
a. The mass of the block is reduced.
i. Shorter
ii. Longer
iii. Unchanged
Explanation:
b. The spring – mass device is transported to the Moon, where the acceleration due to gravity is weaker.
i. Shorter
ii. Longer
iii. Unchanged
Explanation:
c. The stiffness of the spring is reduced (i.e., the spring constant is lowered).
i. Shorter
ii. Longer
iii. Unchanged
Explanation:
d. The amplitude of the oscillation is increased (i.e., the distance the mass travels up and down is increased).
i. Shorter
ii. Longer
iii. Unchanged
Explanation:
3. Consider the frequency of the sound pro
a. The pendulum is transported to another planet where the acceleration due to gravity is smaller.
i. Shorter
ii. Longer
iii. Unchanged
Explanation:
b. The mass of the pendulum increases.
i. Shorter
ii. Longer
iii. Unchanged
Explanation:
c. The length of the pendulum decreases (i.e., the pendulum arm is shortened).
i. Shorter
ii. Longer
iii. Unchanged
Explanation:
d. The distance the pendulum travels or how far it travels from side to side (i.e., the amplitude of oscillation) is reduced.
i. Shorter
ii. Longer
iii. Unchanged
Explanation:
2. Consider a block attached to a spring shown in Figure 9.1.5 of the textbook.
For each of the following scenarios, indicate whether the oscillation period of the block becomes shorter, longer or remains unchanged. Note: you must clearly mark your answer (for example, highlight it in red) from the multiple-choice list below and you must provide an explanation of your answer to receive credit. Review: course textbook (section 9.1).
a. The mass of the block is reduced.
i. Shorter
ii. Longer
iii. Unchanged
Explanation:
b. The spring – mass device is transported to the Moon, where the acceleration due to gravity is weaker.
i. Shorter
ii. Longer
iii. Unchanged
Explanation:
c. The stiffness of the spring is reduced (i.e., the spring constant is lowered).
i. Shorter
ii. Longer
iii. Unchanged
Explanation:
d. The amplitude of the oscillation is increased (i.e., the distance the mass travels up and down is increased).
i. Shorter
ii. Longer
iii. Unchanged
Explanation:
3. Consider the frequency of the sound pro
Answers
Henry
T^2 = 4*pi^2(L/g)
1a. Longer. A smaller g increases the ratio of L/g which increases the
period.
1b. Unchanged. The mass is not included in the Eq.
1c. Shorter. The ratio of L/g decreases which decreases the period.
1d. Unchanged. The ratio of L/g remains the same. Therefore, the period remains the same.
1a. Longer. A smaller g increases the ratio of L/g which increases the
period.
1b. Unchanged. The mass is not included in the Eq.
1c. Shorter. The ratio of L/g decreases which decreases the period.
1d. Unchanged. The ratio of L/g remains the same. Therefore, the period remains the same.