Asked by rex

In the drawing, the weight of the block on the table is 380 N and that of the hanging block is
175 N. Ignore all frictional effects, and assuming the pulley to be massless. What is the
acceleration of the two block?

Answers

Answered by Elena
m₁g+m₂g =(m₁+m₂)g =380+175=555
(m₁+m₂) =555/g=56.6 kg
m₁a =T
m₂a=-T+m₂g
m₂a = - m₁a +m₂g
a=(m₂g)/(m₁+m₂) =
=175/56.6=3.1 m/s²
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