Question

A 0.363 g wire is stretched between two points 80.3 cm apart. The tension in the wire is 573 N.
Find the frequency of first harmonic. Answer in units of Hz

Answer 1

λ=v/f => f = v/ λ,
v = sqrt(TL/m ),
λ=2L,
f = sqrt(TL/m )/ 2L=
=sqrt(573•0.803/0.363•10⁻³)/2•0.803=
=701 Hz

Answer 2

A 0.373 g wire is stretched between two points
89.2 cm apart. The tension in the wire is
533 N.