Question
A 0.363 g wire is stretched between two points 80.3 cm apart. The tension in the wire is 573 N.
Find the frequency of first harmonic. Answer in units of Hz
Find the frequency of first harmonic. Answer in units of Hz
Answers
Elena
λ=v/f => f = v/ λ,
v = sqrt(TL/m ),
λ=2L,
f = sqrt(TL/m )/ 2L=
=sqrt(573•0.803/0.363•10⁻³)/2•0.803=
=701 Hz
v = sqrt(TL/m ),
λ=2L,
f = sqrt(TL/m )/ 2L=
=sqrt(573•0.803/0.363•10⁻³)/2•0.803=
=701 Hz
joe
A 0.373 g wire is stretched between two points
89.2 cm apart. The tension in the wire is
533 N.
89.2 cm apart. The tension in the wire is
533 N.