Asked by Help Me Please

A 0.363 g wire is stretched between two points 80.3 cm apart. The tension in the wire is 573 N.
Find the frequency of first harmonic. Answer in units of Hz

Answers

Answered by Elena
λ=v/f => f = v/ λ,
v = sqrt(TL/m ),
λ=2L,
f = sqrt(TL/m )/ 2L=
=sqrt(573•0.803/0.363•10⁻³)/2•0.803=
=701 Hz
Answered by joe
A 0.373 g wire is stretched between two points
89.2 cm apart. The tension in the wire is
533 N.
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