(a) The same as his initial kinetic energy
(b) The friction force F is
(Initial kinetic energy)/(sliding distance)
F = (1/2) M V^2/X
Divide that by the player's weight (M g) to get the kinetic friction coefficient.
mu,k = F/(M*g) = V^2/(2 g X)
A 62.0-kg baseball player slides 3.40 m from third base w/ a speed of 4.35 m/s. If the player comes to rest in third base , (a) how much work was done on the player by friction? (b) what was the coefficient of the kinetic friction between the player and the ground?
2 answers
After plugging in the values, I obtained the following results:
(a) W = K = -587J
(b) muk = 0.285
(a) W = K = -587J
(b) muk = 0.285