Question

Solve the following system of equations using the cross multiplication method,ax+by=a-b;bx-ay=a+b

Answer 1

http://www.mathcaptain.com/algebra/simultaneous-equations.html

ax +by =a-b
bx-ay=a+b

ax+by +(b-a) = 0
bx –ay +(-a-b) = 0
x y 1
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b ↘ b-a ↘ a ↘ b
-a ↗ -a-b ↗ b ↗ -a
x/{-ab-b²+ab-a²} = y/{b²-ab+a²+ab} = 1/{-a²-b²},
x/{-a²-b²} = 1/{-a²-b²},
x=1.
y/{b² +a²} =1/{-a²-b²},
y=-1.

Answer 2

Cross multiplication methods

Answer 3

Thanks

Answer 4

Thu ela na chesaventi ra neyabba

Answer 5

thanks

Answer 6

Chutiya hai kya

Answer 7

These eq. help me in my problem.