x^2 + 5x - 12 >0
consider x^2 + 5x - 12 = 0
x = (-5 ± √73)/2
x = appr 1.8 or x = appr -6.8
knowing about the shape of the corresponding quadratic function (a parabola opening upwards)
we want the value above the x - axis
x < -6.8 OR x > 1.8
Solve the inequality. Round your answer to the nearest tenth.
x2 + 5⋅x - 7 > 5
1 answer