Asked by madison
A balloon at 32 °C is filled with 21 L of air. What would its volume be at a temperature of 52 °C, assuming pressure remains constant?
Answers
Answered by
Jai
Assuming the gas is ideal, we use Charles' Law to relate the relationship between Temperature & Volume of gas:
V1/T1 = V2/T2
where:
T1 = initial temperature of gas (in K)
T2 = final temperature of gas (in K)
V1 = initial volume of gas
V2 = final volume of gas
*note that to convert °C to K, we just add 273.
substituting,
(21)/(32 + 273) = V2/(52 + 273)
V2 = (21)*(325)/(305)
V2 = ?
now solve for V2.
hope this helps~ :)
V1/T1 = V2/T2
where:
T1 = initial temperature of gas (in K)
T2 = final temperature of gas (in K)
V1 = initial volume of gas
V2 = final volume of gas
*note that to convert °C to K, we just add 273.
substituting,
(21)/(32 + 273) = V2/(52 + 273)
V2 = (21)*(325)/(305)
V2 = ?
now solve for V2.
hope this helps~ :)
Answered by
WTF
I wanted the full answer fam fym solve for V2 Bit!!! you solve for it!!
Answered by
Anonymous
Bruh it's not that hard they literally gave the equation to you it's 22 L. lord save this generation
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