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Barium carbonate and nitric acid:
BaCO3 (s) + 2HNO3 (aq.) --> Ba2+ (aq.) + 2(NO3-) (aq.) + CO2 (g) + H2O (l)

If 25.0mLs of 0.150M nitric acid was used, how many grams of barium carbonate would be required for complete reaction?
12 years ago

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Answered by Anonymous
jlasn
4 years ago
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Barium carbonate and nitric acid:
BaCO3 (s) + 2HNO3 (aq.) --> Ba2+ (aq.) + 2(NO3-) (aq.) + CO2 (g) + H2O (l)

If 25.0mLs of 0.150M nitric acid was used, how many grams of barium carbonate would be required for complete reaction?

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