Asked by Jarrod
A heavier mass m1 and a lighter mass m2 are 18.0 cm apart and experience a gravitational force of attraction that is 9.70 10-9 N in magnitude. The two masses have a combined value of 5.65 kg. Determine the value of each individual mass.
Answers
Answered by
Elena
the gravitational constant G =6.67•10⁻¹¹ N•m²/kg²,
F =G•m₁•m₂/R²
m₁=m
m₂=5.65-m
F =G•m •(5.65-m)/R²
Solve for m
F =G•m₁•m₂/R²
m₁=m
m₂=5.65-m
F =G•m •(5.65-m)/R²
Solve for m
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